The function f(x) = 4x^2/4xx^3 is A discontinuous at only one point B discontinuous at exactly two points C discontinuous at exactly three points D none of theseFind f'(a) f(x) = 3x^2 4x 1 Number thirty one of the Stuart Calculus eighth edition section two point seven Find at time of a the function of life is every X equals three x squared minus for explosive one And for this problem will be using the equation to here I was shown on the rate to figure out at a prem a veinShort Solution Steps f ( x ) = 3 x ^ { 2 } \frac { 3 } { x ^ { 2 } } f ( x) = 3 x 2 − x 2 3 To add or subtract expressions, expand them to make their denominators the same Multiply 3x^ {2} times \frac {x^ {2}} {x^ {2}} To add or subtract expressions, expand them to make their denominators the same Multiply 3 x 2 times x 2 x 2

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Q.1 the function f(x)=(4-x^(2))/(4x-x^(3)) is
Q.1 the function f(x)=(4-x^(2))/(4x-x^(3)) is-If f(x) = 4x – 3 and g(x) = 8x 2, find each function value afg(3) bgf(5) cg{fg(4)} Get the answers you need, now!Click here👆to get an answer to your question ️ The function f(x) = 4 3x 3x^2 x^3 is




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Question For the function f(x) = 3x^4 4x^3 x^2 6x2 a State the degree of the polynomial b State the number of zeros the polynomial function will have c Use the Rational Zero Theorem to list all of the possible rational zeros d Use your calculator to determine which numbers in the list of rational zeros are probable rational/12/16 · This is a composition of functions #f(x)=x3# #g(x)=x^24# #f(g(x))=f(x^24)=x^243=x^21# The range is #f(g(x)) in 1, oo# #g(f(x))=g(x3)=(x3)^24# The range is #g(f(x)) in 4, oo#9 Express 6 !4x 0x2 in the form a 0(x!b)2, where a and b are integers 2 (i) Find the coordinates of the turning point of the curve y #6 !4x 0x2 and determine the nature of this turning point 3 The function f is defined by f x √6 !4x 0x2 for the domain 0 ≤ x ≤ 5 (ii) Find the range of f 2 (iii) State, giving a reason, whether or not f has an inverse 1 4 6 Given that each of
4x4 (2x2 − 1)2 View solution steps Solution Steps f ( x ) = x ( 2 x ^ { 2 } 1 ) ^ { 2 } ( 4 x ^ { 3 } ) f ( x) = x ( 2 x 2 − 1) 2 ( 4 x 3) To multiply powers of the same base, add their exponents Add 1 and 3 to get 4 To multiply powers of the same base, add their exponents Add 1 and 3 to get 4Question 2757 f(x)4x2 4x 3 I need help to find the intercepts, the vertex and the maximun or minimun I know I need to use the quadratic formula, but I don't know how to apply it to find these three points Thank you for your help Martha AnswerGraph f (x)=4 (3)^x f (x) = 4(3)x f ( x) = 4 ( 3) x Exponential functions have a horizontal asymptote The equation of the horizontal asymptote is y
Algebra Examples Popular Problems Algebra Find the Inverse Function f (x)=x^24xAsked Nov 8, 18 in Mathematics by Afreen ( 307k points)The function f is defined by f (x) = x4 −4x2 x 1 for −5 ≤ x ≤ 5 What is the interval in which the minimum of value of f Purely a graphical approximation;




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· Here f(0)= 4 and f(4)=4 Hence according to the Rolle's theorem there should be at least one c for which f'(c)=0 To find c, get #f'(x)=3x^22x12# and equate it to 0 #3x^22x12# =0 and solve for x using quadratic formula x= # (2sqrt (4144))/6#This gives the desired c= #(2sqrt 148)/6# in the interval0,4For the function {eq}\displaystyle f(x) = 3x^4 4x^3 6x^2 12x 1 {/eq} A) Find the critical numbers of the function B) Find the open intervals on which the function · This is the Solution of Question From RD SHARMA book of CLASS 12 CHAPTER CONTINUITY AND DIFFERENTIABILITY This Question is also available in R S AGGARWAL boo




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· Thisis 0 when √x2 −1 = √4 − x2 or 2x2 = 5 or x = ± √25 and where f (x) = 2√15 = √6 Hence, range is √3,√6 graph { sqrt (4x^2) sqrt (x^21)Click here👆to get an answer to your question ️ Show that f R→ R given by f(x) = 3x 4 is one one and onto Find its inverse functionAlso, find f^1 (9) and f^1( 2) · Show that the function f in A = R {2/3} defined as f(x) = (4x3)/(6x4) is oneone and onto Hence, find f^{ –1}



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Consider the function f(x) = x^3 ?𝑓(𝑥)=(4𝑥 − 3)6𝑥 − 4 𝑓(𝑓𝑥) = 4𝑓(𝑥) − 36𝑓(𝑥) − 4 𝑓𝑜𝑓𝑥 = 44𝑥 − 36𝑥 − 4 − 364𝑥 − 36𝑥 − 4A function is written in the form of the ratio of two polynomial functions is called a rational function Rational functions are continuous at all the points except for the points where denominator becomes zero \(f(x)=\dfrac{P(x)}{Q(x)}\) where P(x) and Q(x) are polynomials and Q(x) ≠ 0 f(x) will be discontinuous at points where Q(x) = 0




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The function f (x) = 2x^3 – 3x^2 – 12x 4, has A two points of local maximum B two points of local minimum asked Sep 19, in Derivatives by Chandan01 ( 512k points) application of derivative · Refer Explanation section Given f(x)=3(x4)^25 It is a quadratic equation in the vertex form The vertex form of the quadratic generally is y=a(xh)k Where (h,k) is vertex In our equation h=4 x coordinate of the vertex k=5 y coordinate of the vertex Vertex is (4,5) Take a few values on either side of x=4 Calculate corresponding y values Tabulate itThe Function F ( X ) = 4 − X 2 4 X − X 3 (A) Discontinuous at Only One Point (B) Discontinuous Exactly at Two Points Discontinuous Exactly at Three Points (D) None of These



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